Mathematical Preliminaries for SVM

Mathematical Preliminaries for SVM #

Support Vector Machines use optimisation, geometry and kernels. Before deriving SVM, we need constrained optimisation, Lagrange multipliers, primal and dual problems, KKT conditions, hyperplanes and kernel functions.

Key takeaway: SVM is built on constrained optimisation. The hard-margin SVM primal problem is a quadratic optimisation problem with linear inequality constraints. The dual problem uses Lagrange multipliers and leads naturally to support vectors and kernels.

  • Primal and dual perspectives
  • Geometry of margins

SVM Preliminaries Map #

flowchart TD
    A[SVM Preliminaries] --> B[Constrained Optimisation]
    A --> C[Primal and Dual]
    A --> D[KKT Conditions]
    A --> E[Hyperplanes]
    A --> F[Kernel Functions]
    style A fill:#E1F5FE,stroke:#78909C,stroke-width:1px,color:#263238
    style B fill:#C8E6C9,stroke:#78909C,stroke-width:1px,color:#263238
    style C fill:#FFF9C4,stroke:#78909C,stroke-width:1px,color:#263238
    style D fill:#EDE7F6,stroke:#78909C,stroke-width:1px,color:#263238
    style E fill:#E1F5FE,stroke:#78909C,stroke-width:1px,color:#263238
    style F fill:#C8E6C9,stroke:#78909C,stroke-width:1px,color:#263238

Why These Preliminaries Matter #

The SVM problem asks for a separating hyperplane with maximum margin.

This becomes an optimisation problem:

  • minimise a quadratic function
  • subject to inequality constraints
  • solve using Lagrange multipliers
  • identify active constraints using KKT conditions
  • use kernels when data is not linearly separable

General Constrained Optimisation Problem #

The standard form is:

\[ \min_x f(x) \]

subject to:

\[ g_i(x) \le 0,\quad i=1,2,\ldots,m \]

and:

\[ h_j(x)=0,\quad j=1,2,\ldots,p \]

Here:

  • \( f(x) \) is the objective function
  • \( g_i(x) \) are inequality constraints
  • \( h_j(x) \) are equality constraints

Lagrangian #

The Lagrangian combines the objective and constraints into one expression.

\[ \mathcal{L}(x,\lambda,\nu) = f(x)+\sum_{i=1}^{m}\lambda_i g_i(x)+\sum_{j=1}^{p}\nu_j h_j(x) \]

where:

  • \( \lambda_i \) are Lagrange multipliers for inequality constraints
  • \( \nu_j \) are Lagrange multipliers for equality constraints

For inequality constraints:

\[ \lambda_i \ge 0 \]

For equality constraints, \( \nu_j \) is unrestricted.


Inequality Constraints and Sign Convention #

If the constraint is written as:

\[ g_i(x)\le 0 \]

then the multiplier satisfies:

\[ \lambda_i \ge 0 \]

This is the convention used in convex optimisation.

In SVM derivations, constraints may be written in different equivalent forms. Always check the sign before writing the Lagrangian.


Primal Problem #

The primal problem is the original constrained optimisation problem.

\[ \min_x f(x) \]

subject to:

\[ g_i(x)\le0 \]

The optimisation is performed over the original variables \( x \) . These are called primal variables.


Dual Problem #

The dual function is:

\[ D(\lambda)=\min_x \mathcal{L}(x,\lambda) \]

The dual problem is:

\[ \max_{\lambda} D(\lambda) \]

subject to:

\[ \lambda \ge 0 \]

The variables \( \lambda \) are called dual variables.


Weak Duality #

Weak duality says:

\[ \text{dual optimum} \le \text{primal optimum} \]

For minimisation problems, the dual gives a lower bound on the primal optimum.

In the lecture slides, this appears through the minimax inequality:

\[ \max_y \min_x \phi(x,y) \le \min_x \max_y \phi(x,y) \]

Weak duality always holds under broad conditions.


Strong Duality #

Strong duality says:

\[ \text{dual optimum} = \text{primal optimum} \]

This means we can solve the dual problem and get the same optimal value as the primal problem.

This is useful in SVM because:

  • the dual depends on inner products between data points
  • inner products can be replaced by kernels
  • the solution depends only on support vectors

Slater’s Condition #

Slater’s condition gives a common case where strong duality holds.

For a convex optimisation problem, Slater’s condition holds if:

  1. the objective function \( f \) is convex
  2. the inequality constraints \( g_i \) are convex
  3. the equality constraints \( h_j \) are affine or linear
  4. there exists a strictly feasible point \( \bar{x} \) such that:
\[ g_i(\bar{x}) < 0 \]

and:

\[ h_j(\bar{x}) = 0 \]

If Slater’s condition holds, then strong duality holds.


KKT Conditions #

The Karush-Kuhn-Tucker conditions are the main optimality conditions for constrained optimisation.

For:

\[ \min f(x) \]

subject to:

\[ g_i(x)\le0,\quad h_j(x)=0 \]

the KKT conditions are:

1. Primal Feasibility #

\[ g_i(x^*)\le0 \]

and:

\[ h_j(x^*)=0 \]

2. Dual Feasibility #

\[ \lambda_i^*\ge0 \]

3. Complementary Slackness #

\[ \lambda_i^*g_i(x^*)=0 \]

4. Stationarity #

\[ \nabla f(x^*)+\sum_{i=1}^{m}\lambda_i^*\nabla g_i(x^*)+\sum_{j=1}^{p}\nu_j^*\nabla h_j(x^*)=0 \]

Complementary Slackness Intuition #

Complementary slackness is very important for SVM.

\[ \lambda_i g_i(x)=0 \]

This means:

CaseMeaning
\( \lambda_i=0 \)constraint is not active
\( g_i(x)=0 \)constraint is active
\( \lambda_i>0 \)point lies exactly on the active boundary

In SVM, points with non-zero Lagrange multipliers become support vectors.


Quadratic Programming #

SVM optimisation is a quadratic programming problem.

A standard quadratic programme is:

\[ \min_{x\in\mathbb{R}^d} \frac{1}{2}x^TQx+c^Tx \]

subject to:

\[ Ax\le b \]

The SVM primal has this structure because it minimises:

\[ \frac{1}{2}\|w\|^2 \]

subject to linear constraints involving training points.


Hyperplane #

A hyperplane is a generalised line or plane.

In two dimensions, it is a line. In three dimensions, it is a plane. In \( d \) dimensions, it is a \( (d-1) \) -dimensional hyperplane.

The equation is:

\[ w^Tx+b=0 \]

where:

  • \( w \) is the normal vector
  • \( b \) is the bias or intercept
  • \( x \) is the input vector

Why \( w \) Is Orthogonal to the Hyperplane #

Let \( x_a \) and \( x_b \) lie on the hyperplane.

Then:

\[ w^Tx_a+b=0 \]

and:

\[ w^Tx_b+b=0 \]

Subtract:

\[ w^T(x_a-x_b)=0 \]

So \( w \) is orthogonal to any vector lying inside the hyperplane.

This is why \( w \) determines the orientation of the separating hyperplane.


Distance from a Point to a Hyperplane #

For the hyperplane:

\[ w^Tx+b=0 \]

the distance of a point \( x_0 \) from the hyperplane is:

\[ D=\frac{|w^Tx_0+b|}{\|w\|} \]

This formula is used to derive the SVM margin.


Linear Classifier #

A linear classifier predicts using:

\[ f(x)=w^Tx+b \]

The predicted class is:

\[ \hat{y}=\operatorname{sign}(w^Tx+b) \]

If:

\[ w^Tx+b>0 \]

predict positive class.

If:

\[ w^Tx+b<0 \]

predict negative class.


Kernel Function #

A kernel is a function:

\[ K(x,y) \]

that takes two inputs and returns a real number.

The lecture defines kernels as continuous functions that are symmetric:

\[ K(x,y)=K(y,x) \]

A kernel corresponds to an inner product in some feature space:

\[ K(x_i,x_j)=\phi(x_i)^T\phi(x_j) \]

where \( \phi(x) \) maps the original data to a higher-dimensional feature space.


Why Kernels Matter for SVM #

Linear SVM relies on dot products:

\[ x_i^Tx_j \]

If data is mapped into a higher-dimensional space:

\[ x \mapsto \phi(x) \]

then dot products become:

\[ \phi(x_i)^T\phi(x_j) \]

The kernel trick replaces this with:

\[ K(x_i,x_j) \]

So we do not need to explicitly compute \( \phi(x) \) .


Mercer’s Theorem #

The slides state:

Every positive-semidefinite symmetric function is a kernel function.

This means that if a function is symmetric and positive semidefinite, it can be used as a valid kernel.


Common Kernel Examples #

Linear Kernel #

\[ K(x_i,x_j)=x_i^Tx_j \]

Polynomial Kernel #

\[ K(x_i,x_j)=(1+x_i^Tx_j)^p \]

Sigmoid Kernel #

\[ K(x_i,x_j)=\tanh(\beta_0x_i^Tx_j+\beta_1) \]

RBF-like Distance Kernel #

The slides also mention kernels built from distances:

\[ k(x,x')=\exp(-d(x,x')) \]

where \( d(x,x') \) is a distance function.


Exam Method: KKT Setup #

When asked to write KKT conditions, use this template.

Given:

\[ \min f(x) \]

subject to:

\[ g(x)\le0 \]

write:

Lagrangian #

\[ \mathcal{L}(x,\lambda)=f(x)+\lambda g(x) \]

KKT Conditions #

\[ \nabla_x\mathcal{L}(x,\lambda)=0 \] \[ g(x)\le0 \] \[ \lambda\ge0 \] \[ \lambda g(x)=0 \]

This often gives marks even if the full solution is difficult.


Quick Memory Line #

Constrained optimisation → Lagrangian → Dual → KKT → Hyperplane → Kernel

Source Focus #

This page is based mainly on:

  • Lecture 11: constrained optimisation, Lagrange multipliers, primal and dual problems, weak duality, convex optimisation, quadratic programming
  • Lecture 14: KKT conditions, hyperplanes, kernel functions and linear classifiers
  • Course handout: session 14 and Module 7 SVM preliminaries

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